Multivariable Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 0-53849-787-4
ISBN 13: 978-0-53849-787-9

Chapter 12 - Vectors and the Geometry of Space - 12.6 Exercises - Page 857: 31

Answer

Hyperbolic Paraboloid, center: origin, Traces in y=k are hyperbolas. Traces in x=k, z=k are parabolas.

Work Step by Step

Rewrite: $2y=2z^{2}-x^{2}$ $\displaystyle \frac{y}{1}=\frac{z^{2}}{1}-\frac{x^{2}}{2}$ Comparing the form to Table 1, we find: Hyperbolic Paraboloid $\displaystyle \frac{z}{c}=\frac{x^{2}}{a^{2}}-\frac{y^{2}}{b^{2}},\quad $where Horizontal traces (z=k) are hyperbolas. Vertical traces (x=k, y=k) are parabolas.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.