Multivariable Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 0-53849-787-4
ISBN 13: 978-0-53849-787-9

Chapter 12 - Vectors and the Geometry of Space - 12.6 Exercises - Page 857: 19

Answer

Hyperbolic Paraboloid

Work Step by Step

We can rewrite the equation as: $y=z^{2}-x^{2}$ $ \implies \dfrac{y}{1}=\dfrac{z^{2}}{1}-\dfrac{x^{2}}{1^1}$ So, we find that we have: Hyperbolic Paraboloid $ \dfrac{z}{c}=\dfrac{x^{2}}{a^{2}}-\dfrac{y^{2}}{b^{2}}$ When $z=k$, traces are parabolas opening in the $-y$ direction. Traces are parabolas when $x=k$, opening in the $+y$ direction.
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