Multivariable Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 0-53849-787-4
ISBN 13: 978-0-53849-787-9

Chapter 12 - Vectors and the Geometry of Space - 12.6 Exercises - Page 857: 21

Answer

$VII$

Work Step by Step

The equation $x^{2}+4y^{2}+9z^{2}=1$ is an ellipsoid, so it can be either Figure $IV$ or Figure $VII$. If we write the given equation in the standard form of an ellipsoid centered at the origin, we will have $\frac{x^{2}}{1^{2}}+\frac{4y^{2}}{(1/2)^{2}}+\frac{z^{2}}{(1/3)^{2}}=1$ The numbers $1,1/2$ and $1/3$ are the number of units you go along either side of the $x-, y-$ and $z$-axes, respectively, from the origin, that is, the center of the ellipsoid, to get to the surface of the ellipsoid. Since we can visualize that Figure $VII$, has the ellipsoid more elongated along the x-axis and that 1 (the number under $x^{2})$ is greater than $1/2$ and $1/3$, it must be Figure $VII$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.