Answer
Elliptic cone, axis: y-axis, vertex: origin.
Work Step by Step
Rewrite:
$\displaystyle \frac{y^{2}}{1^{2}}=\frac{x^{2}}{1^{2}}+\frac{z^{2}}{3^{2}}$
comparing with "Cone" in Table 1 (where the axis was the z-axis), here we have the y-axis as the axis, and (0,0,0) as the vertex.
Traces in the planes x=k and z=k are hyperbolas for $k\neq 0$, and straight lines for k=0.
Traces in the y=k planes are ellipses.
