Answer
$(2,3,1)$
Work Step by Step
$x=y-1=2z$
$x=t$,$y-1=t$ and $2z=t$
$x=t$,$y=1+t$ and $z=t/2$
$\implies$ $4t-(1+t)+3(1/2t)=8$
$\implies$ $t=2$
Thus, $x=2,y=1+2=3,z=2/2=1$
Hence, $(2,3,1)$
Multivariable Calculus, 7th Edition
by Stewart, James
Published by
Brooks Cole
ISBN 10:
0-53849-787-4
ISBN 13:
978-0-53849-787-9
Chapter 12 - Vectors and the Geometry of Space - 12.5 Exercises - Page 849: 47
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