Answer
$x=1,y-2=-z$
Work Step by Step
Given: $5x-2y-2z=1$ and $4x+y+z=6$
Here, $(x_0,y_0,z_0)=(1,1,1)$ and $ \lt a,b,c\gt=\lt 0,-13,13\gt$
The symmetric equations are defined by:
$\frac{x-x_0}{a}=\frac{y-y_0}{b}=\frac{z-z_0}{c}$
Hence, the symmetric equations are:
$x=1,y-2=-z$
