Multivariable Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 0-53849-787-4
ISBN 13: 978-0-53849-787-9

Chapter 12 - Vectors and the Geometry of Space - 12.5 Exercises - Page 849: 51

Answer

Perpendicular

Work Step by Step

$x+4y-3=1$ and $-3x+6y+7z=0$ Since the dot product of the two vectors is equal to zero, they are perpendicular. $n_1=\lt1,4,-3\gt$ and $n_2=\lt -3,6,7\gt$ $n_1 \cdot n_2=\lt1,4,-3\gt \cdot \lt -3,6,7\gt$ $n_1 \cdot n_2=-3+24-21$ $n_1 \cdot n_2=0$ Hence, the planes are perpendicular.
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