Answer
$4x+y+2z=2$
Work Step by Step
Mid point of points $(2,5,5)$ and $(-6,3,1)$ is $M=(-2,4,3)$
Normal vector: $n=\lt -8,-2,-4\gt $
Plug in these points and the vector components of the normal vector in the equation of the plane.
Thus, $-8(x+2)-2( y-4)-4(z-3)=0 $
$-8x-16-2y+8-4z+12=0$
$8x+2y+4z=4$
Hence, the equation of the plane is:
$4x+y+2z=2$