Answer
$(1,0,2)$
Work Step by Step
$x+2y-z+1=0$
$\implies$ $1+2t+2(4t)-(2-3t)+1=0$
$\implies$ $13t=0$
$\implies $ $ t=0$
Thus, $x=1+2(0)=1,y=4(0)=0,z=2-3(0)=2$
Hence, $(1,0,2)$
Multivariable Calculus, 7th Edition
by Stewart, James
Published by
Brooks Cole
ISBN 10:
0-53849-787-4
ISBN 13:
978-0-53849-787-9
Chapter 12 - Vectors and the Geometry of Space - 12.5 Exercises - Page 849: 46
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