Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 9 - Section 9.3 - Logarithmic Functions and Models - Exercises - Page 657: 44

Answer

$19.2818=t$ The investment would take approximately 19 years.

Work Step by Step

The future value of a general compound rate can be described with the following function: $A(t)=P*(1+\frac{r}{m})^{mt}$, where $P$ is the amount of investment at $t=0$, $r$ is the compound rate and $t$ is the number of years since the investment and $m$ is the number of compounding times within a year. In this exercise: $A(t)=20,000$ $P=10,400$ $r=0.034$ $m=12$ Therefore the question is to calculate $t$, such as: $20,000=10,400*(1+\frac{0.034}{12})^{12t}$ $\frac{20,000}{10,400}=1.923=(1.00283^{12t})$ $\log_{1.00283}1.923=231.382=12t$ $19.2818=t$ The investment would take approximately 19 years.
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