Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 9 - Section 9.3 - Logarithmic Functions and Models - Exercises - Page 657: 32

Answer

$f(t)=2.3*e^{0.7885t}$

Work Step by Step

We can convert the general function of: $f(t)=A*b^{t}$ as: $f(t)=Q_0*(e^k)^{t}=Q_0*e^{kt}$ In the exercise, we have: $f(t)=2.3*2.2^{t}$ In order to get the desired form of the function we have to convert: $2.2=e^{k}$ We can use the logarithm for this: $\log_e{2.2}=k$ $\ln{2.2}=0.7885=k$ Therefore the result will be: $f(t)=2.3*e^{0.7885t}$
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