Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 9 - Section 9.3 - Logarithmic Functions and Models - Exercises - Page 657: 8

Answer

$6^{3x+1}=30$ $\log_{6}30=3x+1$ $\log_{6}30-1=3x$ $\frac{\log_{6}30-1}{3}=x$ $\frac{0.8982}{3}=x$ $0.2994=x$

Work Step by Step

The definition of the logarithm function can be translated into mathematical formulas such as the following. The given expressions are equivalent. The exponential form: $b^{x}=a$ The logarithmic form: $\log_{b}a=x$. The given equation can be solved with the logarithmic form, therefore we shall transform it: $6^{3x+1}=30$ $\log_{6}30=3x+1$ $\log_{6}30-1=3x$ $\frac{\log_{6}30-1}{3}=x$ $\frac{0.8982}{3}=x$ $0.2994=x$
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