Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 9 - Section 9.3 - Logarithmic Functions and Models - Exercises - Page 657: 12

Answer

$4*1.5^{2x-1}=8$ $1.5^{2x-1}=\frac{8}{4}=2$ $\log_{1.5}2=2x-1$ $\log_{1.06}2.2+1=2x$ $\frac{\log_{1.06}2.2+1}{2}=x$ $\frac{2.7095}{2}=x$ $1.3548=x$

Work Step by Step

The definition of the logarithm function can be translated into mathematical formulas such as the following. The given expressions are equivalent. The exponential form: $b^{x}=a$ The logarithmic form: $\log_{b}a=x$. The given equation can be solved with the logarithmic form, therefore we shall transform it: $4*1.5^{2x-1}=8$ $1.5^{2x-1}=\frac{8}{4}=2$ $\log_{1.5}2=2x-1$ $\log_{1.06}2.2+1=2x$ $\frac{\log_{1.06}2.2+1}{2}=x$ $\frac{2.7095}{2}=x$ $1.3548=x$
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