Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 9 - Section 9.2 - Exponential Functions and Models - Exercises - Page 644: 81

Answer

$S=167\cdot 1.18^{t}$ $1695$ cases.

Work Step by Step

We want an exponential model, $S=Ab^{t}$ At the start, March 17th, $t=0$ days, and the initial size is $A=167$. The increase of $ 18\%$ is a factor of $b=1.18$ So, $S=167\cdot 1.18^{t}$ On March 31st, the number of days passed is $t=14$ and $S=167\cdot 1.18^{14}\approx 1694.58974319\approx 1695$ cases.
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