Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 9 - Section 9.2 - Exponential Functions and Models - Exercises - Page 644: 76a

Answer

Model:$\quad P=2.56(1.01641)^{t}$ billion people

Work Step by Step

Exponential models have the form: $P=Ab^{t}$ Given the points on the graph $(0,2.56)\quad\Rightarrow\quad\left\{\begin{array}{l} 2.56=Ab^{0}\\ A=2.56\\ P=2.56b^{t} \end{array}\right.$ $(61,6.91) $, which is 61 years after 1950 - $\left\{\begin{array}{l} 6.91=2.56b^{61}\\ b^{61}=6.91/2.56\\ b=(6.91/2.56)^{1/61}\\ b\approx 1.01641128142\\ b\approx 1.01641 \end{array}\right.$ Thus, we have the model: $\quad P=2.56(1.01641)^{t}$ billion people
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