Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 9 - Section 9.2 - Exponential Functions and Models - Exercises - Page 644: 82

Answer

$S=1804\cdot 1.04^{t}$ $5626$ cases.

Work Step by Step

We want an exponential model, $S=Ab^{t}$ At the start, April 1st, $t=0$ days, and the initial size is $A=1804$ The daily increase of $ 4\%$ is a factor of $b=1.04$ So, $S=1804\cdot 1.04^{t}$ On April 30th, the number of days passed is $t=29$ and $S=1804\cdot 1.04^{29}\approx 5626$ cases.
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