Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 9 - Section 9.2 - Exponential Functions and Models - Exercises - Page 643: 34

Answer

$2^{\wedge}(3-x)/(1-2^{\wedge}x)$

Work Step by Step

$2^{\wedge}(3-x)/(1-2^{\wedge}x)$ or $(2^{\wedge}(3-x))/(1-2^{\wedge}x)$ There is no real need to enclose the numerator in parentheses, because $2^{\wedge}(3-x)$ is one term. The denominator must be enclosed in parentheses, and the exponent must be enclosed in parentheses, otherwise, for example, $2^{\wedge}3-x/1-2^{\wedge}x \quad $ generates $2^{3}-\displaystyle \frac{x}{1}-2^{x}$, $(2^{\wedge}3-x)/1-2^{\wedge}x \quad $ generates $\displaystyle \frac{2^{3}-x}{1}-2^{x}$, $2^{\wedge}(3-x)/1-2^{\wedge}x \quad $ generates $\displaystyle \frac{2^{3-x}}{1}-2^{x}$, etc.
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