Answer
$f(t)=5000e^{0.10t}$
Work Step by Step
For interest compounded continuously, $f(t)=Pe^{rt}$.
Given $P=5000,\quad r=0.10,$
$f(t)=5000e^{0.10t}$
Finite Math and Applied Calculus (6th Edition)
by Waner, Stefan; Costenoble, Steven
Published by
Brooks Cole
ISBN 10:
1133607705
ISBN 13:
978-1-13360-770-0
Chapter 9 - Section 9.2 - Exponential Functions and Models - Exercises - Page 643: 63
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