Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 9 - Section 9.2 - Exponential Functions and Models - Exercises - Page 643: 56

Answer

$y=-1\left(2^{x}\right)$

Work Step by Step

The exponential function we want has the form $y=Ab^{x}$. $\left[\begin{array}{ll} \text{point on} & \text{corresponding}\\ \text{the graph} & \text{equation}\\ (2,-4) & -4=Ab^{2}\\ (4,-16) & -16=Ab^{4} \end{array}\right]$ Dividing the equations, $\displaystyle \frac{-16}{-4}=\frac{Ab^{4}}{Ab^{2}}$ $4=b^{2}$, so $b=2.$ Back-substituting into the first equation, $-4=A(2)^{2}$ $-4=4A$ $A=-1$ The model is $y=Ab^{x}=-1\left(2^{x}\right)$
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