Answer
$\displaystyle \frac{1}{14}$
Work Step by Step
$P(E)=\displaystyle \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}=\frac{n(E)}{n(S)}$
$n(S)=C(10,4)=210$
$ E$= ($2$ of 2 - T and VZ) AND ($0$ of 2 - PFE, DD)
AND ($2$ of the remaining 6)
$n(E)=C(2,2)\cdot C(2,0)\cdot C(6,2)=15$
$P(E')=\displaystyle \frac{15}{210}=\frac{1}{14}$