Answer
$P(E)=0.000014\lt0.0001$
Work Step by Step
Sample space: all possible combinations of 5 cards from a deck with 52 cards:
$n(S)=C(52,5)=\frac{52!}{(52-5)!\times5!}=\frac{52\times51\times50\times49\times48}{5\times4\times3\times2\times1}=2,598,960$
Choose any suit: $C(4,1)=4$
From this suit, choose the starting card for the flush. It can be: $A,2,3,4,5,6,7,8,9$: $C(9,1)=9$
For the next four cards there is only one option.
$n(E)=4\times9=36$
$P(E)=\frac{n(E)}{n(S)}=\frac{36}{2,598,960}=0.000014\lt0.0001$
