Answer
$P(E)=0.0039$
Work Step by Step
Sample space: all possible combinations of 5 cards from a deck with 52 cards:
$n(S)=C(52,5)=\frac{52!}{(52-5)!\times5!}=\frac{52\times51\times50\times49\times48}{5\times4\times3\times2\times1}=2,598,960$
Choose any card from $A$ to $10$: $C(40,1)=40$
The next four cards must have consecutive denominations. There are four choices for each card.
$n(E)=40\times4\times4\times4\times4=10,240$
$P(E)=\frac{n(E)}{n(S)}=\frac{10,240}{2,598,960}=0.0039$
