Answer
$\displaystyle \frac{1}{5}$
Work Step by Step
$P(E)=\displaystyle \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}=\frac{n(E)}{n(S)}$
$n(S)=C(10,2)=45$
E=( 1 of PFE) AND ( 1 of the other 9)
$n(E)=C(1,1)\cdot C(9,1)=9$
$P(E)=\displaystyle \frac{9}{45}=\frac{1}{5}$