Answer
$\displaystyle \frac{3}{10}$
Work Step by Step
$P(E)=\displaystyle \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}=\frac{n(E)}{n(S)}$
$n(S)=C(10,3)=120$
E=( 1 of PFE) AND ( $2$ of the other 9)
$n(E)=C(1,1)\cdot C(9,2)=36$
$P(E)=\displaystyle \frac{36}{120}=\frac{3}{10}$