Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 4 - Section 4.2 - Matrix Multiplication - Exercises - Page 253: 40

Answer

Answers to a, b, c, d, are all $\left[\begin{array}{ll} 0.1 & 0.9\\ 0.1 & 0.9 \end{array}\right]$

Work Step by Step

$P^{2}=\left[\begin{array}{ll} 0.1 & 0.9\\ 0.1 & 0.9 \end{array}\right]\left[\begin{array}{ll} 0.1 & 0.9\\ 0.1 & 0.9 \end{array}\right]$ $= \left[\begin{array}{ll} 0.1\cdot 0.1+0.9\cdot 0.1 & 0.1\cdot 0.9+0.9\cdot 0.9\\ 0.1\cdot 0.1+0.9\cdot 0.1 & 0.1\cdot 0.9+0.9\cdot 0. \end{array}\right]=\left[\begin{array}{ll} 0.1 & 0.9\\ 0.1 & 0.9 \end{array}\right]=P$ So, $P^{2}=P.$ $b.$ $P^{4}=P^{2}\cdot P^{2}=P\cdot P=P^{2}=P$ $c.$ $P^{8}=P^{4}\cdot P^{4}=P\cdot P=P^{2}=P$ $d.$ All powers of P equal P, so $P^{1,000}=P$
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