Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 4 - Section 4.2 - Matrix Multiplication - Exercises - Page 253: 39

Answer

Answers to a, b, c, d, are all $\left[\begin{array}{ll} 0.2 & 0.8\\ 0.2 & 0.8 \end{array}\right]$

Work Step by Step

$a.$ $P^{2}=\left(\begin{array}{ll}{0.2}&{0.8}\\{0.2}&{0.8}\end{array}\right)\left(\begin{array}{ll}{0.2}&{0.8}\\{0.2}&{0.8}\end{array}\right)=$ $= \left[\begin{array}{ll} 0.2\cdot 0.2+0.8\cdot 0.2 & 0.2\cdot 0.8+0.8\cdot 0.8\\ 0.2\cdot 0.2+0.8\cdot 0.2 & 0.2\cdot 0.8+0.8\cdot 0.8 \end{array}\right]=\left[\begin{array}{ll} 0.2 & 0.8\\ 0.2 & 0.8 \end{array}\right]=P$ So, $P^{2}=P.$ $b.$ $P^{4}=P^{2}\cdot P^{2}=P\cdot P=P^{2}=P$ $c.$ $P^{8}=P^{4}\cdot P^{4}=P\cdot P=P^{2}=P$ $d.$ All powers of P equal P, so $P^{1,000}=P$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.