Answer
$\left[\begin{array}{rrrr}
0 & 1 & 0 & -1\\
0 & 0 & 0 & 0\\
20 & 2 & 2 & -2\\
-10 & -4 & -1 & 4
\end{array}\right]$
Work Step by Step
$B-C=\left[\begin{array}{ll}
-1 & 0\\
0 & 0\\
-2 & 2\\
4 & -1
\end{array}\right]$
$A=\left[\begin{array}{rrrr}
{0}&{-1}&{0}&{1}\\
{10}&{0}&{1}&{0}\end{array}\right]$
$(B-C)A$ is defined and is a 4$\times$4 matrix.
$=\left[\begin{array}{llll}
0+0 & 1+0 & 0+0 & -1+0\\
0 & 0 & 0 & 0\\
0+20 & 2+0 & 0+2 & -2+0\\
0-10 & -4+0 & 0-1 & 4+0
\end{array}\right]$
$=\left[\begin{array}{llll}
0 & 1 & 0 & -1\\
0 & 0 & 0 & 0\\
20 & 2 & 2 & -2\\
-10 & -4 & -1 & 4
\end{array}\right]$
