Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 4 - Section 4.2 - Matrix Multiplication - Exercises - Page 253: 43

Answer

Answers to a,b,c,d are all $\left[\begin{array}{lll} 0.3 & 0.3 & 0.4\\ 0.3 & 0.3 & 0.4\\ 0.3 & 0.3 & 0.4 \end{array}\right]$

Work Step by Step

$a.$ $P^{2}=\left[\begin{array}{lll} 0.3 & 0.3 & 0.4\\ 0.3 & 0.3 & 0.4\\ 0.3 & 0.3 & 0.4 \end{array}\right]$ $=\left[\begin{array}{lll} 0.3\cdot 0.3+0.3\cdot 0.3+0.4\cdot 0.3 & 0.3\cdot 0.3+0.3\cdot 0.3+0.4\cdot 0.3 & 0.3\cdot 0.3+0.3\cdot 0.3+0.4\cdot 0.4\\ 0.3\cdot 0.3+0.3\cdot 0.3+0.4\cdot 0.3 & 0.3\cdot 0.3+0.3\cdot 0.3+0.4\cdot 0.3 & 0.3\cdot 0.3+0.3\cdot 0.3+0.4\cdot 0.4\\ 0.3\cdot 0.3+0.3\cdot 0.3+0.4\cdot 0.3 & 0.3\cdot 0.3+0.3\cdot 0.3+0.4\cdot 0.3 & 0.3\cdot 0.3+0.3\cdot 0.3+0.4\cdot 0.4 \end{array}\right]$ $=\left[\begin{array}{lll} 0.3 & 0.3 & 0.4\\ 0.3 & 0.3 & 0.4\\ 0.3 & 0.3 & 0.4 \end{array}\right]$ $P^{2}=P $ so $P^{3}=P^{2}\cdot P=P\cdot P=P^{2}=P,$ $P^{4}=P^{3}\cdot P=P\cdot P=P^{2}=P$ ... (all powers of P equal P) $P^{4}=P^{8}=P^{1000}=P$ Answers to a,b,c,d are all $\left[\begin{array}{lll} 0.3 & 0.3 & 0.4\\ 0.3 & 0.3 & 0.4\\ 0.3 & 0.3 & 0.4 \end{array}\right]$
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