Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 4 - Section 4.2 - The Mean Value Theorem - 4.2 Exercises: 25

Answer

$ f(4)=16$

Work Step by Step

$f'(x) = \frac{f(4) - 10}{4-1}$ $f'(x) = \frac{f(4) - 10}{3}$ Multiply by $3$ on both sides to cancel the denominator. $3f'(x) = f(4) - 10$ $3f'(x) + 10 = f(4)$ Given: $f'(x) = 2$ $3(2) + 10 = f(4)$ $6 + 10 = f(4)$ $16 = f(4)$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.