Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 1 - Section 1.3 - New Functions from Old Functions - 1.3 Exercises: 56

Answer

a) $r=2t$ b) $V(r(t))=\frac{32}{3}\pi t^{3},$ the volume of the balloon as a function of time.

Work Step by Step

a) Rate of increase of radius$=\frac{r}{t}=2$ $r=2t$ b) $V(r(t))=\frac{4}{3}\pi r^{3}=\frac{4}{3}\pi (2t)^{3}=\frac{32}{3}\pi t^{3}$ This is the volume of the balloon as a function of time.
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