Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 1 - Section 1.3 - New Functions from Old Functions - 1.3 Exercises: 49

Answer

$h(x)=\sqrt x$ $g(x)=x-1$ $f(x)=\sqrt x$

Work Step by Step

Separating the function into three processes: $1. h(x)=\sqrt x$ $2.g(h(x))=g(\sqrt x)=\sqrt x-1=h(x)-1$ $g(x)=x-1$ $3.f(g(h(x)))=f(\sqrt x-1)=\sqrt {\sqrt x-1}=\sqrt {g(h(x))}$ $f(x)=\sqrt x$
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