Answer
$g(t)=\tan t$
$f(t)=\frac{t}{1+t}$
Work Step by Step
Separating the function into two processes:
$1. g(t)=\tan t$
$2. f(g(t))= f(\tan t)=\frac{\tan t}{1+\tan t}=\frac{g(t)}{1+g(t)}$
$f(t)=\frac{t}{1+t}$
Calculus: Early Transcendentals 8th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1285741552
ISBN 13:
978-1-28574-155-0
Chapter 1 - Section 1.3 - New Functions from Old Functions - 1.3 Exercises - Page 44: 48
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