Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 1 - Section 1.3 - New Functions from Old Functions - 1.3 Exercises: 47

Answer

$g(t)=t^{2}$ $f(t)=\sec t\tan t$

Work Step by Step

Separating the function into two processes: $1. g(t)=t^{2}$ $2. f(g(t))=f(t^{2})=\sec t^{2}\tan t^{2}=\sec g(t)\tan g(t)$ $f(t)=\sec t\tan t$
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