Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 1 - Section 1.3 - New Functions from Old Functions - 1.3 Exercises: 46

Answer

$g(x)=\frac{x}{1+x}$ $f(x)=\sqrt[3] x$

Work Step by Step

Separating the function into two processes: $1. g(x)=\frac{x}{1+x}$ $2. f(g(x))=f(\frac{x}{1+x})=\sqrt[3] \frac{x}{1+x}=\sqrt[3] (g(x))$ $f(x)=\sqrt[3] x$
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