Answer
$f(-3)=-2, f(0)=0, f(2)=4$
On the graph, $f(-1)=0$.
Work Step by Step
$f(x)=x+1$ for $x\leq-1$ and $f(x)=x^2$ for $x\gt-1$
$f(-3)=-3+1\Rightarrow f(-3)=-2$
$f(0)=0^2\Rightarrow f(0)=0$
$f(2)=2^2\Rightarrow f(2)=4$
Calculus: Early Transcendentals 8th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1285741552
ISBN 13:
978-1-28574-155-0
Chapter 1 - Section 1.1 - Four Ways to Represent a Function - 1.1 Exercises - Page 21: 43
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