## Calculus: Early Transcendentals 8th Edition

$y=1-\sqrt {-x}$
We start with $x + (y-1)^2=0$. Subtract both sides by $x$. $(y-1)^2=-x$ Take the negative square root of both sides, because we need to get the bottom half of the parabola. $y-1=-\sqrt {-x}$. Add 1 to both sides. $y=1-\sqrt {-x}$.