Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 1 - Section 1.1 - Four Ways to Represent a Function - 1.1 Exercises: 35

Answer

$x\lt0$ or $x\gt5$

Work Step by Step

$\because h(x)$ is defined for all real x where the denominator is not equal to zero $[\sqrt[4] (x^{2}-5x)\ne0, x^{2}-5x\ne0$], and only the fourth root of non-negative numbers is real $[x^{2}-5x\geq0]$ $\therefore x^{2}-5x\gt0,$ $x(x-5)\gt0,$ $x\lt0$ or $x\gt5$
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