## Calculus: Early Transcendentals 8th Edition

$y=\sqrt {4-x^2}+2$
We start with $x^2+(y-2)^2=4$. Subtract $x^2$ from both sides. $(y-2)^2=4-x^2$ Take the square root of both sides. $y-2=\sqrt {4-x^2}$ Add 2 to both sides. $y=\sqrt {4-x^2} + 2$