Answer
The domain of $g(t)$ is: $(-∞,-1) \cup (-1,∞)$
Work Step by Step
$g(t) = \frac{t^{2} - 1}{t + 1}$ has one restriction at $t = -1$ (undefined). Otherwise, it becomes a line:
$g(t)=\frac{(t+1)(t-1)}{(t+1)}=t-1$
Calculus: Early Transcendentals 8th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1285741552
ISBN 13:
978-1-28574-155-0
Chapter 1 - Section 1.1 - Four Ways to Represent a Function - 1.1 Exercises - Page 21: 40
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