Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 4 - Applications of the Derivative - 4.2 What Derivatives Tell Us - 4.2 Exercises - Page 257: 59

Answer

$f$ is concave up on $(−∞, 0)$, concave down on $(0, 2)$, and concave up on $(2,∞)$. There are inflection points at $x = 0$ and $x = 2$.

Work Step by Step

$f'(x) = 20x^3 −60x^2$, and $f''(x) = 60x^2 −120x = 60x(x−2)$. This is $0$ for $x = 0$ and for $x = 2$. Note that $f(−1) > 0$, $f(1) < 0$, and $f(3) > 0$. So $f$ is concave up on $(−∞, 0)$, concave down on $(0, 2)$, and concave up on $(2,∞)$. There are inflection points at $x = 0$ and $x = 2$.
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