Answer
$x = 0$ is a critical point which yields a local maximum.
Work Step by Step
$f'(x) = −2x$, so $x = 0$ is a critical point. $f''(x) = −2$, so $f(0) = −2$ and the critical point yields a local maximum.
Calculus: Early Transcendentals (2nd Edition)
by Briggs, Bill L.; Cochran, Lyle; Gillett, Bernard
Published by
Pearson
ISBN 10:
0321947347
ISBN 13:
978-0-32194-734-5
Chapter 4 - Applications of the Derivative - 4.2 What Derivatives Tell Us - 4.2 Exercises - Page 257: 73
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