Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 4 - Applications of the Derivative - 4.2 What Derivatives Tell Us - 4.2 Exercises - Page 257: 31

Answer

$f$ is increasing on $(−∞,∞)$ and $f$ is never decreasing.

Work Step by Step

$f'(x) = \frac{1}{x^2+1}$, which is always positive, so $f$ is increasing on $(−∞,∞)$ .
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