Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 4 - Applications of the Derivative - 4.2 What Derivatives Tell Us - 4.2 Exercises - Page 257: 34

Answer

$f$ is decreasing on $(0, 1)$ and increasing on $(1,∞)$.

Work Step by Step

$f'(x) = 2x − \frac{2}{x} = \frac{2(x^2−1)}{x}$ which is $0$ for $x =\pm1$. Note that the domain of $f$ is $(0,∞)$ and that $f'(1/2) = −3 < 0$ and $f'(2) = 3 > 0$, so $f$ is decreasing on $(0, 1)$ and increasing on $(1,∞)$.
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