Answer
$$1$$
Work Step by Step
Given
$$\lim_{x\to0}\frac{\sec x}{1-\sin x}$$
Since
\begin{align*}
\lim_{x\to0}\frac{\sec 0}{1-\sin 0}&=\lim_{x\to0}\frac{1}{1-0}\\
&=1
\end{align*}
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