Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 2 - Derivatives - Review - Exercises - Page 197: 17

Answer

$2x\sin \pi x+\pi x^{2}\cos \pi x$

Work Step by Step

$y=x^{2}\sin \pi x\Rightarrow y'=\left( \dfrac {d}{dx}x^{2}\right) \times \sin \pi x+\left( \dfrac {d}{dx}\sin \pi x\right) \times x^{2}=2x\sin \pi x+\pi x^{2}\cos \pi x$
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