Answer
$\dfrac {3}{5\sqrt [5] {x^{8}}}-\dfrac {1}{2\sqrt {x^{3}}}$
Work Step by Step
$y=\dfrac {1}{\sqrt {x}}-\dfrac {1}{\sqrt [5] {x^{3}}}=x^{-\dfrac {1}{2}}-x^{-\dfrac {3}{5}}\Rightarrow y'=-\dfrac {1}{2}x^{-\dfrac {3}{2}}+\dfrac {3}{5}x^{-\dfrac {8}{5}}=\dfrac {3}{5\sqrt [5] {x^{8}}}-\dfrac {1}{2\sqrt {x^{3}}}$
