Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 2 - Derivatives - Review - Exercises: 19

Answer

$\dfrac {8t^{3}}{\left( t^{4}+1\right) ^{2}}$

Work Step by Step

$y=\dfrac {t^{4}-1}{t^{4}+1}=\dfrac {t^{4}+1-2}{t^{4}+1}=1-\dfrac {2}{\left( t^{4}+1\right) }\Rightarrow y'=\dfrac {2\times \left( 4t^{3}\right) }{\left( t^{4}+1\right) ^{2}}=\dfrac {8t^{3}}{\left( t^{4}+1\right) ^{2}}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.