Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.7 - Complex Numbers - Exercise Set: 80

Answer

$-\dfrac{5}{7}i$

Work Step by Step

Multiply both the numerator and the denominator by the conjugate of the denominator, which is $-7i$, to obtain: $=\dfrac{5(-7i)}{7i(-7i)} \\=\dfrac{-35i}{-49i^2}$ Use the fact that $i^2=-1$ to obtain: $=\dfrac{-35i}{-49(-1)} \\=\dfrac{-35i}{49} \\=-\dfrac{5(7)}{7(7)}i \\=-\dfrac{5}{7}i$
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