Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.7 - Complex Numbers - Exercise Set: 52

Answer

$5 + 12i$

Work Step by Step

RECALL: (1) $(a+b)^2 = a^2+ 2ab + b^2$ (2) $i^2=-1$ Use rule (1) above with $a=3$ and $b=2i$ to obtain: $=3^2 +2(3)(2i) + (2i)^2 \\=9 +12i + 4i^2$ Use rule (2) above to obtain: $=9 +12i + 4(-1) \\=9+12i+(-4) \\=5 + 12i$
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