Answer
$-11-5i$.
Work Step by Step
The given expression is
$=(2-3i)(1-i)-(3-i)(3+i)$
$=(2-2i-3i+3i^2)-(3^2-i^2)$
Use $i^2=-1$.
$=(2-2i-3i-3)-(9+1)$
Clear the parentheses.
$=2-2i-3i-3-9-1$
Add like terms.
$=-11-5i$.
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 7 - Section 7.7 - Complex Numbers - Exercise Set - Page 570: 101
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